Q) What is iota raised to the power iota? (i = sqrt(-1) )

A)

cos@ + i.sin@ = e^(i.@)

if we take @ = pi/2:

i = e^(i.pi*/2)

Raise both sides to exponent i:

i^i = e^ (i.pi/2 . i)

i^i = e^(-pi/2)

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## Monday, August 11, 2008

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## 7 comments:

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cos@ + i.sin@ = e^(i.@) where does this come from???????

Euler's formula: https://www.wikiwand.com/en/Euler's_formula

Euler form to represent a complex number. Basically here r=1 and e^(i.@) represent argument

Is the answer is Real No. or Complex.

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