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Monday, August 11, 2008

Q) What is iota raised to the power iota? (i = sqrt(-1) )

A)
cos@ + i.sin@ = e^(i.@)
if we take @ = pi/2:
i = e^(i.pi*/2)
Raise both sides to exponent i:
i^i = e^ (i.pi/2 . i)
i^i = e^(-pi/2)


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7 comments:

Anonymous said...

thanks

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Anonymous said...

good job

Anonymous said...

cos@ + i.sin@ = e^(i.@) where does this come from???????

spideyunlimited said...

Euler's formula: https://www.wikiwand.com/en/Euler's_formula

Anonymous said...

Euler form to represent a complex number. Basically here r=1 and e^(i.@) represent argument



Anonymous said...

Is the answer is Real No. or Complex.