Q) If f(x) is sum of all digits of x then

f(101)+f(102)+f(103).................f(200) is ?

A) 99(1) for hundreds places + 10(1+2+3+4+5+6+7+8+9) for tens places + 10(1+2+3+4+5+6+7+8+9) for units places + 2 for 200

= 99 + 20(45) + 2

= 101 + 900

= 1001

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## Monday, August 11, 2008

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