Q) A circle touches the x axis and also touches another fixed circle with center (0,3) and radius = 2 units. What is the locus of the center of the (first) circle?
A) Consider any such arbitrary circle, with center (h,k).
It touches the x axis, so its radius is k units ( the ordinate).
Now, the distance of this circle's center from the given circle's center = 2 + k units
This distance is the same as the distance between center of the arbitrary circle and the line y = -2 .
Now, since the center of this arbitrary circle is equidistant from a fixed point (the center of given circle ie. (0,3) ) and the line y = -2, it follows the definition of the parabola and hence the locus of (h,k) is a parabola.
So the locus of the center of the circle is a parabola with focus (0,3) and directrix y = -2 .
________________________________________________________
Saturday, December 13, 2008
Subscribe to:
Post Comments (Atom)
4 comments:
please help me
Q: How to find number of terms in the expansion
(1+x+x^2+x^3)^8
by a easier way or if their is a general formula please tell.....
please help me
Q: How to find number of terms in the expansion
(1+x+x^2+x^3)^8
by a easier way or if their is a general formula please tell.....
please help me
Q:How to find number of terms in the expansion (1+x+x^2+x^3) by an easier way or is their an easier way to find number of terms please help me...............
please help me
Q:How to find number of terms in the expansion (1+x+x^2+x^3) by an easier way or is their an easier way to find number of terms please help me...............
Post a Comment